- Aug 21, 2015 · I just got asked a question about a good way to find the closest value in a vector that was less than a threshold. My solution is fairly short, and demonstrates some of my favorite MATLAB techniques. I will compare also show you an "obvious" solution.
- The step function is one of most useful functions in MATLAB for control design. Given a system representation, the response to a step input can be immediately plotted, without need to actually solve for the time response analytically. A step input can be described as a change in the input from zero to a finite value at time t = 0
- I needed a Matlab function for Huffman coding/decoding to be used in a course of mine. Since I was not able to find anything I liked, I wrote it by myself. Here you can find both a "pure .m" version and two C versions: a MEX file one and a stand-alone program to be called via the system call. A warning: since I wrote these functions for my ...
- Display version information for MATLAB, Simulink, and toolboxes version Get MATLAB version number web Point Help browser or Web browser at file or Web site what diary List MATLAB-specific files in current directory whatsnew Display README files for MATLAB and toolboxes which Locate functions and files Edit an M
- The largest value in C maps to the last row in the colormap array. The intermediate values in C map linearly to the intermediate rows of the colormap array. You can adjust this mapping using the caxis function. The CData property of the Surface object stores the values of C.
- In any n-dimensional space, the two lines L 1 and L 2 are closest at unique points P C = P (s C) and Q C = Q (t C) for which w(s C, t C) is the unique minimum for w(s,t). Further, if L 1 and L 2 are not parallel and do not intersect each other, then the segment P C Q C joining these points is uniquely simultaneously perpendicular to both lines.
- Feb 05, 2009 · "Xiaodong" wrote in message <[email protected]>... > This is an interesting problem, similar to my present problem: > Back to the original problem, yet, I do not only attempt to find the closest value from a to b, but also attempt to replace the closest value in a to that in b, and return the index of being replaced elements in a.
- Its two arguments are the damping ratio and natural frequency [these may be vectors if you want to look at a range of acceptable values]. In our problem, we need an overshoot less than 5% (which means a damping ratio of greater than 0.7) and a rise time of 1 second (which means a natural frequency greater than 1.8).